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Class 10mathsCBSE 2026-27

NCERT Solutions for Class 10 maths Chapter 1: Real Numbers

2 Solved Questions & Exercises2 min estimated readingUpdated 2026-09-16
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NCERT Class 10 Mathematics Solutions
Chapter 1: Real Numbers

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Exercise 1.1Q1 Q2 Q3Q4Q5

Exercise 1.2Q1 Q2 Q3 Q4 Q5 Q6 Q7

Exercise 1.3Q1 Q2 Q3

Exercise 1.4Q1

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Q2

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Q3

1. Euclid’s division lemma :
Given positive integers a and b, there exist whole numbers q and r satisfying .

2. Euclid’s division algorithm :This is based on Euclid’s division lemma.

According to this, the HCF of any two positive integers a and b, with a > b, is obtained as follows:
Step 1 : Apply the division lemma to find q and r where a = bq + r, 0 ≤ r < b.
Step 2 : If r = 0, the HCF is b. If r ≠ 0, apply Euclid’s lemma to b and r.
Step 3 : Continue the process till the remainder is zero. The divisor at this stage will be
HCF (a, b). Also, HCF(a, b) = HCF(b,r).

3. The Fundamental Theorem of Arithmetic :
Every composite number can be expressed (factorised) as a product of primes, and this factorisation is unique, apart from the order in which the prime factors occur.

4. If p is a prime and p divides a2, then p divides q, where a is a positive integer.

5. Let x be a rational number whose decimal expansion terminates. Then we can express x in the form p/q, where p and q are co-prime, and the prime factorisation of q is of the form , where n, m are non-negative integers.

6. Let x = p/q be a rational number, such that the prime factorisation of q is of the form 2^n.5^m,where n, m are non-negative integers. Then x has a decimal expansion which terminates.

7. Let x = p/q be a rational number, such that the prime factorisation of q is not of the form , where n, m are non-negative integers. Then x has a decimal expansion which is non-terminating repeating (recurring).

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