NCERT Class 10 Mathematics Solutions
Chapter 8: Introduction to Trigonometry
Get FreeEx 8.1 Introduction to Trigonometry Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 8.1 Class 10 Maths NCERT Solutions were prepared by ExperiencedTeachers. Detailed answers of all the questions inChapter 8 Maths Class 10 Introduction to TrigonometryExercise 8.1 Provided in NCERT Textbook.
Topics and Sub Topics in Class 10 Maths Chapter 8 Introduction to Trigonometry:
Section Name | Topic Name |
8 | Introduction to Trigonometry |
Question 1 (8)
1 | Introduction |
8.2 | Trigonometric Ratios |
8.3 | Trigonometric Ratios Of Some Specific Angles |
8.4 | Trigonometric Ratios Of Complementary Angles |
8.5 | Trigonometric Identities |
8.6 | Summary |
- Class 10 Maths Introduction to Trigonometry Ex 8.1
- प्रश्नावली 8.1 का हल हिंदी में
- Introduction to Trigonometry Class 10 Ex 8.2
- प्रश्नावली 8.2 का हल हिंदी में
- Introduction to Trigonometry Class 10 Ex 8.3
- प्रश्नावली 8.3 का हल हिंदी में
- Introduction to Trigonometry Class 10 Ex 8.4
- प्रश्नावली 8.4 का हल हिंदी में
- Introduction to Trigonometry Class 10 Extra Questions
Board | CBSE |
Textbook | NCERT |
Class | Class 10 |
Subject | Maths |
Chapter | Chapter 8 |
Chapter Name | Introduction to Trigonometry |
Exercise | Ex 8.1 |
Number of Questions Solved | 11 |
Category | NCERT Solutions |
Ex 8.1 Class 10Maths Question 1.
In ∆ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine:
(i) sin A, cos A
(ii) sin C, cos C

Ex 8.1 Class 10 Maths Question 2.
In given figure, find tan P – cot R.
Solution:

You can also download the freePDF of Chapter 8 Ex 8.1 Introduction to Trigonometry NCERT Solutionsor save the solution images and take the print out to keep it handy for your exam preparation.
Ex 8.1 Class 10 Maths Question 3.
If sin A = , calculate cos A and tan A.
Solution:

Ex 8.1 Class 10 Maths Question 4.
Given 15 cot A = 8, find sin A and sec A.
Solution:

Ex 8.1 Class 10 Maths Question 5.
Given sec θ = , calculate all other trigonometric ratios.
Solution:

Ex 8.1 Class 10 Maths Question 6.
If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
Solution:

Ex 8.1 Class 10 Maths Question 7.
If cot θ = , evaluate:
(i) \)
(ii) cot²θ
Solution:

Ex 8.1 Class 10 Maths Question 8.
If 3 cot A = 4, check whether = cos² A – sin² A or not.
Solution:

Ex 8.1 Class 10 Maths Question 9.
In triangle ABC, right angled at B, if tan A = , find the value of:
(i) sin A cos C + cos A sin C
(ii) cos A cos C – sin A sin C
Solution:


Ex 8.1 Class 10 Maths Question 10.
In ΔPQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
Solution:

Ex 8.1 Class 10 Maths Question 11.
State whether the following statements are true or false. Justify your answer.
(i) The value of tan A is always less than 1.
(ii) sec A = for some value of angle A.
(iii) cos A is the abbreviation used for the cosecant of angle A.
(iv) cot A is the product of cot and A.
(v) sin θ = for some angle.
Solution:

Class 10 Maths Introduction To Trigonometry
Trigonometry
Trigonometry is the study of relationships between the sides and angles of a right-angled triangle.
Trigonometric Ratios
Trigonometric ratios of an acute angle in a right triangle express the relationship between the angle and the length of its sides.
Let ∆ABC be a triangle right angled at B. Then the trigonometric ratios of the angle A in right ∆ABC are defined as follows:


Note:
The values of the trigonometric ratios of an angle do not vary with the lengths of the sides of the triangle, if the angle remains same.

Trigonometric Ratios for Complementary Angles
sin (90° – A) = cos A
cos (90° – A) = sin A
tan (90° – A) = cot A
cot (90° – A) = tan A
sec (90° – A) = cosec A
cosec (90° – A) = sec A
Note:
Here (90° – A) is the complementary angle of A.
Trigonometric Identities
An equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angle(s) involved.
(i) sin2θ + cos2θ = 1 [for 0° ≤ θ ≤ 90°]
(ii) sec2θ – tan2θ = 1 [for 0° ≤ θ ≤ 90°]
(iii) cosec2θ – cot2θ = 1 [for 0° < θ ≤ 90°]
Ex 8.1








We hope the