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NCERT Solutions for Class 11 chemistry Chapter 1: Some Basic Concepts of Chemistry

65 Solved Questions & Exercises18 min estimated readingUpdated 2026-09-16
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NCERT Class 11 Chemistry Solutions
Chapter 1: Some Basic Concepts of Chemistry

Topics and Subtopics in:

Section Name

Topic Name

1

Some Basic Concepts of Chemistry

Question 1 (1)

1

Importance of Chemistry

1.2

Nature of Matter

1.3

Properties of Matter and their Measurement

1.4

Uncertainty in Measurement

1.5

Laws of Chemical Combinations

1.6

Dalton’s Atomic Theory

1.7

Atomic and Molecular Masses

1.8

Mole Concept and Molar Masses

1.9

Percentage Composition

1.10

Stoichiometry and Stoichiometric Calculations

NCERT SolutionsClass 11 ChemistryChemistry Lab ManualChemistry Sample Papers

NCERT TEXTBOOK QUESTIONS SOLVED

Question 1

Calculate the molecular mass of the following:
(i)H20(ii)C02(iii) CH4

Solution:
(i) Molecular mass of H2O = 2(1.008 amu) + 16.00 amu=18.016 amu
(ii) Molecular mass of CO2= 12.01 amu + 2 x 16.00 amu = 44.01 amu
(iii) Molecular mass of CH4= 12.01 amu + 4 (1.008 amu) = 16.042 amu
Question 2

Calculate the mass percent of different elements present in sodium sulphate (Na2SO4).
Answer:

Some Basic Concepts of Chemistry Diagram 1

Some Basic Concepts of Chemistry Diagram 2

More CBSE Class 11 Study Material

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Question 3

Determine the empirical formula of an oxide of Iron which has 69.9 % iron and 30.1 % dioxygen by mass.
Answer:

Some Basic Concepts of Chemistry Diagram 3

Question 4

Calculate the amount of carbon dioxide that could be produced when
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
Answer:The balanced equation for the combustion of carbon in dioxygen/air is

(i) In air, combustion is complete. Therefore,C02produced from the combustion of 1 mole of carbon = 44 g.(ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant. Hence,C02produced = 22 g.(iii) Here again, dioxygen is the limiting reactant. 16 g of dioxygen can combine only with 0.5 mole of carbon.C02produced again is equal to 22 g.

Some Basic Concepts of Chemistry Diagram 4

Question 5

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 gmol-1

Solution:
0.375 M aqueous solution means that 1000 mL of the solution contain sodium acetate = 0.375 mole

Some Basic Concepts of Chemistry Diagram 5

Question 6

Calculate the concentration of nitric acid in moles per litre in a sample which has a density 1.41 gmL-1and the mass percent of nitric acid in it is being 69%.
Answer:Mass percent of 69% means that 100 g of nitric acid solution contain 69 g of nitric acid by mass.
Molar mass of nitric acid HNO3= 1 + 14 + 48 = 63 gmol-1

Some Basic Concepts of Chemistry Diagram 6

Question 7

How much copper can be obtained from 100 g of copper sulphate (CuSO4)? (Atomic mass of Cu= 63.5 amu)
Answer:1 mole of CuS04contains 1 mole (1 g atom) of Cu

Molar mass of CuS04= 63.5 + 32 + 4 x 16 = 159.5 g mol-1

Thus, Cu that can be obtained from 159.5 g of CuS04= 63.5 g

Some Basic Concepts of Chemistry Diagram 7

Question 8

Determine the molecular formula of an oxide of iron in which the mass percent of iron and oxygen are 69.9 and 30.1 respectively. Given that the molar mass of the oxide is 159.8 gmol-1(Atomic mass: Fe = 55.85, O = 16.00 amu)Calculation of Empirical Formula. See Q3.

Solution:
Empirical formula mass of Fe203= 2 x 55.85 + 3 x 16.00 = 159.7 g mol–1


Hence, molecular formula is same as empirical formula, viz.,Fe203.

Some Basic Concepts of Chemistry Diagram 8

Question 9

Calculate the atomic mass (average) of chlorine using the following data:

Answer:

Some Basic Concepts of Chemistry Diagram 9

Some Basic Concepts of Chemistry Diagram 10

Question 10

In three moles of ethane (C2H6), calculate the following:
(i) Number of moles of carbon atoms (ii) Number of moles of hydrogen atoms
(iii) Number of molecules of ethane
Answer:(i) 1 mole of C2H6contains 2 moles of carbon atoms
.•. 3 moles of C2H6will C-atoms = 6 moles
(ii) 1 mole of C2H6contains 6 moles of hydrogen atoms
.•. 3 moles of C2H6will contain H-atoms = 18 moles

Some Basic Concepts of Chemistry Diagram 11

Question 11

What is the concentration of sugar (C12H22O11) in molL-1if its 20 g are dissolved in enough water to make a final volume up to 2 L?

Solution:

Some Basic Concepts of Chemistry Diagram 12

Question 12

If the density of methanol is 0.793 kgL-1, what is its volume needed for making 2.5 L of its 0.25 M solution?
Answer:

Some Basic Concepts of Chemistry Diagram 13

Question 13

Pressure is determined as force per unit area of the surface. The S.I. unit of pressure, pascal, is as shown below:1 Pa = 1Nm-2.If mass of air at sea level is 1034 gcm-2,calculate the pressure in pascal.

Solution:
Pressure is the force (i.e., weight) acting per unit area But weight = mg

Some Basic Concepts of Chemistry Diagram 14

Question 14

What is the S.I. unit of mass?
Answer:S.I. unit of mass is kilogram (kg).

Question 15

Match the following prefixes with their multiples:

Answer:

Some Basic Concepts of Chemistry Diagram 15

Some Basic Concepts of Chemistry Diagram 16

Question 16

What do you mean by significant figures?
Answer:The digits in a properly recorded measurement are known as significant figures. It is also defined as follows. The total numbers of figures in a number including the last digit whose value is uncertain is called number of significant figures.

Question 17

A sample of drinking water was found to be severely contaminated with chloroform, CHCly supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).
(i) Express this in percent by mass
(ii) Determine the molality of chloroform in the water sample.
Answer:

Some Basic Concepts of Chemistry Diagram 17

Question 18

Express the following in scientific notation:
(i) 0.0048 (v) 6.0012 (ii) 234,000 (iii) 8008 (iv) 500.0
Answer:

Some Basic Concepts of Chemistry Diagram 18

Question 19

How many significant figures are present in the following?
(i) 0.0025 (ii) 208 (iii) 5005 (iv) 126,000
(v) 500.0 (vi) 2.0034
Answer:(i) 2 (ii) 3 (iii) 4 (iv) 3 (v) 4 (vi) 5.

Question 20

Round up the following upto three significant figures:
(i) 34.216 (ii) 10.4107 (iii) 0.04597 (iv) 2808
Answer:(i) 34.2 (ii) 10.4 (iii) 0.0460 (iv) 2810

Question 21

The following data were obtained when dinitrogen and dioxygen react together to form compounds:

Answer:(a) Fixing the mass of dinitrogen as 28 g, masses of dioxygen combined will be 32,64, 32 and 80 g in the given four oxides. These’are in the ratio 1 : 2 : 1 : 5 which is a simple whole number ratio. Hence, the given data obey the law of multiple proportions.

Some Basic Concepts of Chemistry Diagram 19

Some Basic Concepts of Chemistry Diagram 20

Question 22



Answer:

Some Basic Concepts of Chemistry Diagram 21

Some Basic Concepts of Chemistry Diagram 22

Question 23

In the reaction, A + B2——> AB2, identify the limiting reagent, if any, in the followingmixtures
(i) 300 atoms of A + 200 molecules ofB
(ii) 2 mol A + 3 mol B
(iii) 100 atoms of A + 100 molecules ofB
(iv) 5 mol A + 2.5 mol B
(v) 2.5 mol A + 5 mol B
Answer:(i) According to the given reaction, 1 atom of A reacts with 1 molecule of B
.•. 200 molecules of B will react with 200 atoms of A and 100 atoms of A will be
left unreacted. Hence, B is the limiting reagent while A is the excess reagent.
(ii) According to the given reaction, 1 mol of A reacts with 1 mol of B
.•. 2 mol of A will react with 2 mol of B. Hence, A is the limiting reactant.
(iii) No limiting reagent.
(iv) 2.5 mol of B will react with 2.5 mol of A. Hence, B is the limiting reagent.
(v) 2.5 mol of A will react with 2.5 mol of B. Hence, A is the limiting reagent.

Question 24

Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:(i)N2(g) + 3H2(g) —–> 2NH3 (g)
(ii) Will any of the two reactants remain unreacted?
(iii) If yes, which one and what would be its mass?
Answer:

Some Basic Concepts of Chemistry Diagram 23

Question 25

How are 0.50 molNa2C03and 0.50 MNa2C03different?
Answer:Molar mass of Na2C03= 2 x 23 + 12 + 3 x 16 = 106g mol-10.50 mol Na2C03means 0.50 x 105 g = 53 g0. 50 M Na2C03 means 0.50 mol, i.e., 53 g Na2C03are present in 1 litre of the solution.

Question 26

If ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour could be produced?
Answer:H2and 02react according to the equation

2H2(g) + 02(g) ——>2H2O(g)

Thus, 2 volumes of H2react with 1 volume of 02to produce 2 volumes of water vapour. Hence, 10 volumes of H2will react completely with 5 volumes of 02to produce 10 volumes of water vapour.

Question 27

Convert the following into basic units:
(i) 28.7 pm (ii) 15.15 µs (iii) 25365 mg
Answer:

Some Basic Concepts of Chemistry Diagram 24

Question 28

Which one of the following will have largest number of atoms?
(i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g ofCl2(g) (Atomic masses: Au = 197, Na = 23, Li = 7, Cl = 35.5 amu)

Solution:

Some Basic Concepts of Chemistry Diagram 25

Question 29

Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040.
Answer:

Some Basic Concepts of Chemistry Diagram 26

Question 30



Answer:

Some Basic Concepts of Chemistry Diagram 27

Some Basic Concepts of Chemistry Diagram 28

Question 31

How many significant figures should be present in the answer of the following?

Answer:(i) The least precise term has 3 significant figures (i.e., in 0.112). Hence, the answer should have 3 significant figures.
(ii) Leaving the exact number (5), the second term has 4 significant figures. Hence, the answer should have 4 significant figures.
(iii) In the given addition, the least number of decimal places in the term is 4. Hence, the answer should have 4 significant.

Some Basic Concepts of Chemistry Diagram 29

Question 32

Use the data given in the following table to calculate the molar mass of naturally occurring argon.

Answer:Molar mass of Ar = 35.96755 x 0.00337 + 37.96272 x 0.00063 + 39.96924 x 0.99600 = 39.948 g mol-1

Some Basic Concepts of Chemistry Diagram 30

Question 33

Calculate the number of atoms in each of the following:
(i) 52 moles of He (ii) 52 u of He (iii) 52 g of He
Answer:

Some Basic Concepts of Chemistry Diagram 31

Some Basic Concepts of Chemistry Diagram 32

Question 34

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at S.T.P.) of this welding gas is found to weigh 11.6 g. Calculate (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula.
Answer:

Some Basic Concepts of Chemistry Diagram 33

Question 35

Calcium carbonate reacts with aqueous HCl according to the reaction

CaC03(s) + 2HCl (aq) ———->CaCl2(aq) +C02(g) +H2O(l).

What mass of CaC03is required to react completely with 25 mL of 0.75 M HCl?
Answer:Step 1.To calculate mass of HCl in 25 mL of 0.75 m HCl
1000 mL of 0.75 M HCl contain HCl = 0.75 mol = 0.75 x 36.5 g = 24.375 g

Step 2.To calculate mass of CaC03reacting completely with 0.9125 g of HCl
CaC03(s) + 2HC1 (aq)———->CaCl2(aq) +C02(g) + H2O
2 mol of HCl, i.e., 2 x 36.5 g = 73 g HCl react completely with CaC03= 1 mol = 100 g

Some Basic Concepts of Chemistry Diagram 34

Some Basic Concepts of Chemistry Diagram 35

Question 36

Chlorine is prepared in the laboratory by treating manganese dioxide (Mn02) with aqueous hydrochloric acid according to the reaction.
4 HCl (aq) + Mn02(s) ———–> 2 H2O (l) + MnCl2(aq) +Cl2(g)

How many grams of HCl react with 5.0 g of manganese dioxide? (Atomic mass of Mn = 55 u)
Answer:1 mole of Mn02, i.e., 55 + 32 = 87 g Mn02react with 4 moles of HCl, i.e., 4 x 36.5 g = 146 g of HCl.

Some Basic Concepts of Chemistry Diagram 36

MORE QUESTIONS SOLVED

Question 2 (I)

Very Short Answer Type Questions
Question1. What is the SI unit of molarity?

Solution:
SI unit of molarity = mol dm-3
Question 2

What do you understand by stoichiometric coefficients in a chemical equation?
Answer:The coefficients of reactant and product involved in a chemical equation represented by the balanced form, are known as stoichiometric coefficients.
For example, N2(g) + 3H2(g) ———–> 2 NH3(g)
The stoichiometric coefficients are 1, 3 and 2 respectively.

Question 3

Give an example of a molecule in which the ratio of the molecular formula is six times the empirical formula.
Answer:The compound is glucose. Its molecular formula is C6H12O6, while empirical formula is CH2O.

Question 4

What is an atom according to Dalton’s atomic theory?
Answer:According to Dalton’s atomic theory, an atom is the ultimate particle of matter which cannot be further divided.

Question 5

Why air is not always regarded as homogeneous mixture?
Answer:This is due to the presence of dust particles.

Question 6

Define the term ‘unit’ of measurement.
Answer:It is defined as the standard of reference chosen to measure a physical quantity.

Question 7

Define law of conservation of mass.
Answer:It states that matter can neither be created nor destroyed.

Question 8

How is empirical formula of a compound related to its molecular formula?
Answer:Molecular formula = (Empirical formula)n where n is positive integer.

Question 9

How many oxygen atoms are there in 18 g of water?
Answer:Molar mass of water is 18 g/mol.
Number of oxygen atoms is 18 g of water = 6.02 x 1023

Question 10

Name two factors that introduce uncertainty into measured figures.
Answer:(i) Reliability of measuring instrument.
(ii) Skill of the person making the measurement.

Question 11

State Avogadro’s law.
Answer:Equal volumes of all gases under the conditions of same temperature and pressure contain the same number of molecules.

Question 12

How are 0.5 ml of NaOH differents from 0.5 M of NaOH?
Answer:0.5 ml of NaOH means 0.5 mole (20.0 g) of NaOH, 0.5M of NaOH means that 0.5 mole (20.0g) of NaOH are dissolved in 1L of its solution.

Question 13

What is one a.m.u. or one ‘u’?
Answer:1 a.m.u. or 1 u = 1/12 th mass of an atom of carbon 12.

Question 14

What is the number of significant figures in 1.050 x 104?
Answer:Four.

II. Short Answer Type Questions
Question 1. Define molality. How does molality depend on temperature?
Answer:Molality is defined as the moles of solute per kilogram of solvent.

Molality of a solution does not depend on temperature.

Some Basic Concepts of Chemistry Diagram 37

Question 2

Convert 2.6 minutes in seconds.
Answer:We know that, 1 min = 60 s
Conversion factor =60 s/(1min)
2.6 min = 2.6 min x conversion factor = 2.6 x 60s/1min= 156 s.

Question 3

Express the following up to four significant figures.

Answer:

Some Basic Concepts of Chemistry Diagram 38

Some Basic Concepts of Chemistry Diagram 39

Question 4

Calculate the number of moles in each of the following.
Answer:


Some Basic Concepts of Chemistry Diagram 40

Some Basic Concepts of Chemistry Diagram 41

Some Basic Concepts of Chemistry Diagram 42

Question 5

A compound on analysis was found to contain C = 34.6%, H = 3.85% and O = 61.55%. Calculate the empirical formula.
Answer:Step I.Calculation of simplest whole number ratios of the elements.

The simplest whole number ratios of the different elements are: C:H:O::3:4:4
Step II.Writing the empirical formula of the compound.
The empirical formula of the compound = C3H4O4.

Some Basic Concepts of Chemistry Diagram 43

Question 6

Calculate:
(a) Mass of 2.5 gram atoms of magnesium,
(b) Gram atom in 1.4 grams of nitrogen (Atomic mass Mg = 24, N = 14)
Answer:(a) 1 gram atom of Mg = 24g
2.5 gram atoms of Mg = 24 x 2.5 = 60g
(b) 1 gram atom of N = 14g;
14g of N = 1 gram atom 1
1.4g of N = 1/14 x 1.4 = 0.1 gram atom.

Question 7

The density of water at room temperature is 1.0 g/mL. How many molecules are there in a drop of water if its volume is 0.05 mL?
Answer:

Some Basic Concepts of Chemistry Diagram 44

Some Basic Concepts of Chemistry Diagram 45

Question 8

What is the molecular mass of a substance each molecule of which contains 9 atoms of carbon, 13 atoms of hydrogen and 2.33 x10-23g other component?

Solution:

Some Basic Concepts of Chemistry Diagram 46

III. Long Answer Type Questions
Question 1. Calculate no. of carbon and oxygen atoms present in 11.2 litres ofC02at N.T.P.

Solution:
Step I.Number of C02molecules in 11.2 litres

Some Basic Concepts of Chemistry Diagram 47

Question 2

KCl03on heating decomposes to give KCl and 02. What is the volume of 02at N.T.P liberated by 0.1 mole ofKCl03?

Solution:
The chemical equation for the decomposition of KCl03is

Some Basic Concepts of Chemistry Diagram 48

Question 3

10 ml of a solution of NaCl containing KCl gave on evaporation 0.93 g of the mixed salt which gave 1.865 g of AgCl by reacting withAgN03solution. Calculate the quantity of NaCl in 10 mL of the solution.

Solution:
The chemical equation for the reaction is:

Some Basic Concepts of Chemistry Diagram 49

Question 4

The cost of table salt (NaCl) and table sugar (C12H22O11) are Rs 1 per kg and Rs 6 per kg respectively.Calculate their cost per mole.
Answer:(a) Cost of table salt (NaCl) per mole
Gram molecular mass of NaCl = 23 + 35.5 = 58.5 g Now, 1000 g of NaCl cost = Rs 2

(b) Cost of table sugar (C12H22O11) per mole
Gram molecular mass of (C12H22O11) = 12 x 12 + 22 x 1 = 16 x 1= 144 + 22 + 176 = 342 g
Now, 1000 g of sugar cost = Rs 6

Some Basic Concepts of Chemistry Diagram 50

Some Basic Concepts of Chemistry Diagram 51

Question 5

A flask P contains 0.5 mole of oxygen gas. Another flask Q contains 0.4 mole of ozone gas. Which of the two flasks contains greater number of oxygen atoms?
Answer:1 molecule of oxygen (O2) = 2 atoms of oxygen
1 molecule of ozone (O3) = 3 atoms of oxygen

Some Basic Concepts of Chemistry Diagram 52

Question 6

Calculate the total number of electrons present in 1.6 g of methane.
Answer:

Some Basic Concepts of Chemistry Diagram 53

Question 7

The vapour density of a mixture ofN02andN204is 38.3 at 27°C. Calculate the number of moles ofN02in 100 g of the mixture.

Solution:

Some Basic Concepts of Chemistry Diagram 54

Question 8

The Vapour Density of a gaseous element is 5 times that of oxygen under similar conditions. If the molecule is triatomic, what will be its atomic mass?
Answer:Molecular mass of oxygen = 32 u

Some Basic Concepts of Chemistry Diagram 55

Some Basic Concepts of Chemistry Diagram 56

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