NCERT Solutions • Class 7 Science (Curiosity) |
Chapter-wiseChapter 8 Measurement of Time and Motion Class 7 Questions and Answers are useful for focused study.
Class 7 Science Chapter 8 Measurement of Time and Motion Question Answer
Science Class 7 Chapter 8 Question Answer Measurement of Time and Motion
Measurement of Time and Motion Class 7 Question Answer (InText)
Question 1
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Question 2
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Question 3
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NCERT Class 7 Science Chapter 8 Question Answer Measurement of Time and Motion (Exercise)
Question 1
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Question 2
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Runner 2:
Distance = 400 m,
Time = 50 s
SPeed = = = 8.89 m/s
Difference = 8.89 – 8 = 0.89 m/s
Hence, speed of runner 2 is greater by approximately 0.89 m/s.
Question 3
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Question 4
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Question 5
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Question 6
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Non-uniform motion: If an object covers unequal distances in equal interval of time, its motion is said to be non-uniform. A car moving in a traffic is an example of nonuniform motion.
Question 7
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Time (s) | 0 | 10 | 20 | 30 | 50 | 70 | ||
Distance (m) | 0 | 8 | 24 | 32 | 40 | 56 |
In uniform motion, object covers equal distances in equal intervals of time. Hence, the speed of an object remains constant throughout the motion.
Time (s) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 |
Distance (m) | 0 | 8 | 16 | 24 | 32 | 40 | 48 | 56 |
The object covers 8 m in every 10 seconds. Hence, the speed of an object remains constant at 0.8 m/s throughout the motion.
Question 8
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Question 9
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Examples:
• Travelling in a bus on an uneven road
• Playing cricket
• Walking through a crowded market
Question 10
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Time interval (s) | Distance (m) |
0-10 | 6 – 0 = 6 |
10-20 | 10 – 6 = 4 |
20-30 | 16 – 10 = 6 |
30-40 | 21 – 16 = 5 |
40-50 | 29 – 21 = 8 |
50-60 | 35 – 29 = 6 |
60-70 | 42 – 35 = 7 |
70-80 | 45 – 42 = 3 |
80-90 | 55 – 45 = 10 |
90-100 | 60 – 55 = 5 |
The object exhibits non-uniform motion, because it covers unequal distances in equal time intervals.
Total distance travelled = 60 m
Total time taken = 100 s
Average speed =
=
= 0.6 m/s
Question 11
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Step 2: Time taken to cover the next 500 m
Time = = 100 s
Step 3: Remaining distance = 2000 – 1000 = 1000 m
Remaining time = 200 – 150 = 50 s
Step 4: Speed required to cover the remaining 1000 m
Speed = = 20 m/s
Step 5: Average speed = = = 10 m/s
Class 7 Measurement of Time and Motion Question Answer (Activities)
Activity 8.1: Let Us Construct (Page 107)
Do it yourself.
Activity 8.2: Let us Experiment (Pages 109-110)
Do it yourself.
Activity 8.3: Let Us Identify (Page 112)
Look at the wall clock shown in Fig. 8.9 carefully. What is the smallest interval of time you can measure with it?
• One second is the smallest interval of time that we can measure using this clock.

Activity 8.4: Let Us Calculate (Pages 114-115)
Table 8.2: Finding the speed of trains Name of the railway station nearest to your place of stay Delhi.
Name of the train | Name of the next station | Distance till the next station (km) | Time taken till the next station(N | Speed of the train between these two stations (km/h) |
Vande Bharat | Ambala Cantt. | 214 | 2h 12 min | 97.27 |
Shatabdi Express | Aligarh | 158 | 1h 30 min | 105.33 |
Tejas Express | Kota | 465 | 2h | 232.5 |
Shan-e-Punjab | Panipat | 99 | 1h 25 min | 69.88 |
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